844. Backspace String Compare - LeetCode Solution

class Solution:
    def backspaceCompare(self, S: str, T: str) -> bool:
        s = []
        t = []

        for i in range(len(S)):

            if(S[i] == "#"):
                if(len(s) != 0):

                    s.pop()
            else:
                s.append(S[i])

        for i in range(len(T)):

            if (T[i] == "#"):
                if (len(t) != 0):
                    t.pop()
            else:
                t.append(T[i])


        return s==t